a man age is three times the sum of the age of his two sons 5 year hence his age is double the sum of the age of his son what is his present age

Question

it' is mathematics question of algebra thank you

Answer 1

x = man's age

y = sum of son's ages

 

man is 3 times as old as sum of sons ages

x = 3y   {equation 1}

 

5 years hence (from now) he will be double

the sum of sons ages.  Since y represents the 

sum of 2 ages, in 5 years y will increase by 10.

 

x + 5 = 2(y + 10)

x + 5 = 2y + 20

x = 2y + 15   {equation 2}

 

since x also equals 3y then

 

3y = 2y+15

y = 15

 

x = 3y = 45

 

The man is 45 years old.

 

check:

x+5 = 2(y+10)

50 = 2(25)

50 = 50

 

 

 

Answer 2

m=man's age

s₁,s₂ son's ages

m=3s₁+3s₂

m+5=2(s₁+5)+2(s₂+5)

Now let s=s₁+s₂ and have

m=3s

m+5=2s+20

3s+5=2s+20

s=15,m=45

Please forgive the nonsense comment above. y+5=y+10 has no sense