Distance equals rate times time

Question

Cyclist began a 627 mi bike ride across a state western edge if the state, at the same time a that a car traveling it leaves the eastern end. If the bycicle and car met after 9.5 hr and the car traveled 34.6 mph faster than the bycicle, find the rate of each

Answer 1

d_bike = r(9.5)

d_car = (r + 34.6)(9.5)

d_bike + d_car = 627

r(9.5) + (r + 34.6)(9.5)

 

Can you solve for t and answer?