How can I solve 2x

^{2}-3=15-
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How can I solve 2x^{2}-3=15

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Isolate the x term onto one side of the equation, divide both sides by the constant of the x term, and take the square root of both sides.

2x^{2} - 3 = 15

2x^{2 }= 18

x^{2} = 9

x = 3 or x = -3

Note that the square root of 9 is 3 or -3, both are solutions.

(-3)^{2} = -3*-3= 9

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