(x-3) (x

^{2 }+ 4x - 21) =0HELP PLEASE

with work please :)

(x-3) (x^{2 }+ 4x - 21) =0

HELP PLEASE

with work please :)

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Wallingford, CT

This is the zero product property. Either x-3 = 0 or x^{2} +4x -21 = 0. So solve each of the two equations, factoring the second term.

x-3 = 0

x = 3

x^{2} +4x -21 = 0

x^{2} - 3x + 7x -21 = 0

x(x - 3) + 7(x-3) = 0

(x-3)(x+7) = 0

Using the zero product property, x = 3 or x = -7

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