answer is not an integer, leave it in simplest radical form.

8*2 = 16

96 * 8(square root of 3) = 1330.2

Area = 665.12 in.

X = 6

6*2 = 12

72 * 6(square root of 3) = 748.3

Area = 374.1m

I am not certain of my answers, and I would greatly appreciate if you could check them for me. Any help is great!

The question is what is the area of the regular polygon with the given radius or apothem? If your

answer is not an integer, leave it in simplest radical form.

answer is not an integer, leave it in simplest radical form.

Question 1) The first shape is a square with an apothem of 6. I figured that since the sides are equal each side equaled double the apothem and amounted to 12. Then I did 12*4 = 48. 48 * 48 = 2304, which made area = 2304 cm^2.

Question 2) The second shape is a hexagon with an apothem of 8* the square root of 3. To solve this I did 360 degrees divided by the 6 sides. Then tan(30 degrees) = x / 8 (square root of 3).

X = 8

8*2 = 16

96 * 8(square root of 3) = 1330.2

Area = 665.12 in.

8*2 = 16

96 * 8(square root of 3) = 1330.2

Area = 665.12 in.

Question 3) The third shape is another hexagon with an apothem of 6* the square root of three. To solve this I did 360 degrees divided by the 6 sides. Then tan(30 degrees) = x / 6 (square root of 3).

X = 6

6*2 = 12

72 * 6(square root of 3) = 748.3

Area = 374.1m

X = 6

6*2 = 12

72 * 6(square root of 3) = 748.3

Area = 374.1m

Tutors, sign in to answer this question.

a regular hexagon is composed of 6 equilateral triangles, in which case, the apothem length is the height of each triangle as it is perpendicular to a side of the hexagon.

As such, it forms a 30-60-90 right triangle.

We can then calculate the length of a triangle side by

Sin 60o = apothem length/hypotenuse

Sin 60o = (8√3)/h

0.8 = (8√3)/h

h = (8√3)/0.8 h = 17.3

with the height of 8√3, and a side of the triangle at 17.3, we can then calculate the area of the hexagon using the area of a triangle multiplied by 6

in this case side = 17.3, and height = 8√3, which is 13.85

thus, the area of each triangle will be ½(17.3 * 13.85) = 120

so, the area of the hexagon will be 6 *120 = 720 units

in like manner, for problem 3, the apothem is 6√3 (10.4)

sin 60o = 10.4 / side

0.80 = 10.4 / s

s = 10.4/0.8 = 13

area = 6 [1/2(13 * 10.4)] = 6 * 67.6 = 406 units

if, however, the hexagons are irregular, then more information will be necessary to solve the problems. that is, enough information to define the 6 triangles which form the hexagon

Rachel,

Not sure what you are doing on # 2 and 3. On question 1 however, the apothem =6 so the side is 2*6=12 as you stated but the area of a square is equal to one side squared A=s^{2} so the area is 12^{2} or 144 sq units.

Hope this helps

Jim

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