Dayaan M. answered 08/26/26
Algebra 1 Honors EOC Score 4/5 – Strong Foundation, Now Helping Others
Happy to check these. Two of them are right and one has a slip in it, so let us go through them.
The formula that handles every regular polygon at once is:
A = (1/2)(apothem)(perimeter)
It is worth seeing where that comes from. Slice the polygon from the center into triangles, one per side. Each triangle has the side as its base and the apothem as its height, so each has area (1/2)(side)(apothem). Adding them all up, the sides combine into the perimeter and you get the formula above.
Question 1, the square with apothem 6. Your first step is right. In a square the apothem reaches from the center to the middle of a side, so the full side is 2 times 6 = 12, and the perimeter is 48. But then the area got mixed up. You squared the PERIMETER instead of the side:
A = (1/2)(6)(48) = 144
or just as easily, side times side, 12 x 12 = 144. So it is 144 cm^2, not 2304.
Question 2, the hexagon with apothem 8sqrt(3). Your setup with the 30 degree angle is exactly right, and you correctly got a half side of 8, so the full side is 16 and the perimeter is 96:
A = (1/2)(8sqrt(3))(96) = 384sqrt(3)
Remember, the problem asked for simplest radical form when the answer is not an integer. So the answer to write down is 384sqrt(3) in^2 rather than the decimal. Your 665.12 is that same number rounded, so your arithmetic was fine, it just needs to stay exact.
Question 3, the hexagon with apothem 6sqrt(3). Same method, side of 12 and perimeter of 72:
A = (1/2)(6sqrt(3))(72) = 216sqrt(3)
Again, leave it as 216sqrt(3) m^2 instead of 374.1.
So, our final answers are 144 cm^2, 384sqrt(3) in^2, and 216sqrt(3) m^2. Your method was solid on all three, the only real error was squaring the perimeter on the square, and the rest is just remembering to leave radicals exact when the problem asks for it.