degree help

Question

A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by

T(t) = 37 + 46e^ – 0.058 t

 

Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)

Answer 1

A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by:

T(t) = 37 + 46e^–0.058t

 

Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)

 

The problem tells you that t = time in minutes, so just set t=10 in T(t) then use your calculator to compute the answer.

 

T(t=10) = 37 + 46e^-0.058(10) = 37 + 46e^-0.58 = ?