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A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by
T(t) = 37 + 46e^ – 0.058 t
 
Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)
5/10/2014 | Theresa from Milltown, NJ | 1 Answer | 0 Votes
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A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by:

T(t) = 37 + 46e–0.058t
 
Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)
 
The problem tells you that t = time in minutes, so just set t=10 in T(t) then use your calculator to compute the answer.
 
T(t=10) = 37 + 46e-0.058(10) = 37 + 46e-0.58 = ?
5/10/2014 | Philip P.

Comments

Yes it is.  Good job!
5/10/2014 | Philip P.