Philip P. answered • 05/10/14

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*A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 37° F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by:*

*T(t) = 37 + 46e*

^{–0.058t}*Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)*

The problem tells you that t = time in minutes, so just set t=10 in T(t) then use your calculator to compute the answer.

T(t=10) = 37 + 46e

^{-0.058(10)}= 37 + 46e^{-0.58}= ?Philip P.

Yes it is. Good job!

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