Let f(x)=3x-1 and g(x)=x^2+4
find (f g)(-2)
f(x ) = 3X -1 g( x ) = X^2 +4
( f +g) ( -2 )= [( 3(-2) -1 +(-2^2) + 4] =
= ( -6 - 1 +4 +4 ) = 1
( f - g ) ( -2) = [ 3(-2) -1 - ( -2^2 +4 ) ]=
= ( -7 -8) = -15
(f ° g ) (-2 ) = [ 3 (-2^2 + 4) - 1 ] =
= 3( 8) - 1 = 23
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