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solution of the equation

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1 Answer

For equations of the form: ax2+bx+c=0, use the quadratic formula:
 
x=[-b±√(b2-4ac)]/2a
 
2x2+6x=1  (first set equation to zero)
 
2x2+6x-1=0
 
a=2
b=6
c=-1
 
 
x=[-b±√(b2-4ac)]/2a
 
 =[-6±√(62-4(2)(-1))]/2(2)
 
 =[-6±√(36+8)]/4
 
 =[-6±√(44)]/4
 
 =[-6±2√11]/4
 
 =[-3±√11]/2

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