
Patrick D. answered 05/21/17
Tutor
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(10)
Patrick the Math Doctor
Please stop posting the question twice. Thank you.
Three consecutive even integers X, X+2, X+4
X^2 + (x+2)^2 = (x+4)^2
x^2 + (x^2 + 4x + 4) = x^2 + 8x + 16
2x^2 + 4x + 4 = x^2 + 8x + 16
x^2 - 4x - 12 = 0 <-- everything to the left side
(x - 6)(x+2) = 0
x=6 or x = -2
First case: 6,8, and 10
36 + 64 = 100 = 10^2
Second case:
-2, 0 , and 2
(-2)^2 + 0^2 = 4 + 0 = 4 = 2^2
So there are 2 sets of 3 consecutive integers that meet this condition:
6,8, and 10 and -2,0, and 2