x^2-3x-4=0

Question

I'm supposed to solve this by graphing.

(if integral roots cannot be found,estimate the roots to the nearest tenth)

Answer 1

I can't graph here.

x^2-3x-4=0

4=4*1 and 4-1=3, the coefficient of the middle term (without the sign)

(x-4)(x+1)=0 (FOIL: x^2-4x+1x-4(1)=x^2-3x-4)

x-4=0

x=4

x+1=0

x=-1