Hi Kali,
If the alleles follow Mendelian genetics these would be the result you would see in F2 offspring.
F1 AA x aa the progeny would be Aa and all would show the dominat phenotype
F2 On selfing the F1 progeny the cross would be Aa x Aa. If you draw a punnet square for this cross you would get a ratio of 1:2:1 Homozygous dominant : 2(Heterozygous dominant) : Homozygous recessive which will be AA:2(Aa):aa
Please let me know if you need further explanation.
Best
Sanjay