What are the mole fractions of glucose and water in a solution containing 5.67g of glucose (C6 H12 O6) dissolved in 25.2g of water?

Question

i need to know how to work this problem 

Answer 1

 

- Start by calculating the molar mass of glucose and water.

 

Molar mass glucose (C₆H₁₂O₆) = 6(12) + 12(1) + 6(16)

72 + 12 + 96  = 180 g/mol Glucose

 

Molar mass water (H₂O) = 2(1) +1(16)

2 + 16 = 18 g/mol Water

 

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- Use molar mass of each to solve for the number of moles of each.

 

5.67g of glucose / 180 g/mol glucose = 0.0315 mol Glucose

 

25.2g of water / 18 g/mol Water = 1.4 mol water

 

Total:

1.4 mol water + 0.0315 mol Glucose = 1.4315 mol solution

 

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- Calculate mole fractions of each

 

Mole fraction Glucose = 0.0315 mol glucose / 1.4315 mol solution

0.0315/1.4315 = 0.022

 

Mole fraction Water = 1.4 mole water / 1.4315 mol solution

1.4/1.4315 = 0.978