
Babita K. answered 03/08/17
Tutor
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Math, Science, and Writing Tutor with Lots of Experience
Hi Ali,
This is a great question that combines percentages and solving for variables. Let's break this question down phrase by phrase.
1) plant A produce[d] 4000 fewer panels than plant B did - We can write this in math as A=B-4000 where A represents the number of panels produced by factory A and B represents the number of panels produced by factory B
2) Two percent of panels from Plant A and 5% of the panels B were de[f]ective - 2 percent is 0.02 and 5 percent is 0.05. So if Ad and Bd represent the number of defective panels produced by factories A and B, respectively, then we can write
Ad = 0.02A
Bd = 0.05B
3) the two plants together produce 970 de[f]ective panels - this means that Ad+Bd=970
4) How many panels did plant B produce - To find B, we can substitute for variables in the equations that we already have.
Ad+Bd=970
Since we know what Ad and Bd are in equation form, we can write
0.02A+0.05B=970
We also know that A=B-4000. So, we can substitute for A.
0.02(B-4000)+0.05B=970
Now, we can solve for B using algebra.
0.02(B-4000)+0.05B=970
0.02B-80+0.05B=970
0.07B-80=970
0.07B=1050
B=15,000