
Jason W. answered 03/04/17
Tutor
4.8
(4)
Georgia Tech PhD student for Physics and Statistics
Hooke's law for a spring is
F=k*x
where F is the force stretching the spring, k is the spring constant, and x is the displacement of the spring.
Any information regarding the length of the spring is given by the value 15cm, which is the original length of the spring plus the displacement due to applied forces. Since we know k = 120 N/m, we have the force and the displacement to figure out.
The problem states that the force on the spring when free-hanging comes from the ball of mass 540g, or Fy=(0.54 kg)*(9.81 m/s2) = 5.2974 N. This force is due to gravity and pulls the spring downward.
Then you pull the ball to the right, exerting a purely horizontal force on the ball and thus the spring. We don't care so much about this horizontal force. We care about the force on the spring since we have that spring length information. So, in order to find the force on the spring, which is along the hypotenuse, we need to know the angle at which this force is being applied.
We are given the length of the spring and the base length which gives us two sides to a right triangle which we can use to find our force. So, let's find the third side using Pythagorean theorem.
152 = 82 + y2
y = 12.689
Now, use ratios to find the force on the spring. In this case, we do the y-component over the hypotenuse.
12.689/15 = 5.2974/F
F = 6.262 N
Now use Hooke's Law to find the displacement.
F=k*x
6.262 = 120*x
x = 5.2186 cm
This is the displacement of the spring at the angled configuration. We know the full length of the spring is 15cm, so then
15 - 5.2186 = 9.7813 cm
So, 9.78 cm is your relaxed length of the spring.
Note: You could find the angle and use sine and cosine to calculate your values, but I find it easier to not mess with them if I don't have to.