Solve for X in the following

Question

 

a) |3x − 8| = 10

 


b) ( 2x - 3) > 11

          2

 

 

 

c) |3x + 9| ≤ 10

Answer 1

a) |3x − 8| = 10  is equivalent to two equations: 3x - 8 = 10  or  3x - 8 = -10; you will get two solutions.

 

c) |3x + 9| ≤ 10  is equivalent to the compound statement   -10  ≤ 3x + 9 ≤ 10; to solve this, subtract

9 from each of the three parts, then divide each of the three parts by 3; you will get x lying between two particular numbers (not necessarily integers), including those endpoints.

 

b)  there's a stray number (2(floating around this, so it's unclear; it appears that this will be a DISJUNCTION type of solution. Would you care to clarify this part of your inquiry?