Steve S. answered 02/26/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
P(x) = 129(1.017)^(x-1992)
139 = 129(1.017)^(x-1992)
(1.017)^(x-1992) = 139/129
(x-1992) log(1.017) = log(139/129)
x-1992 = (log(139/129))/(log(1.017))
x = 1992 + (log(139/129))/(log(1.017))
x ≈ 1996.42908051684203 ≈ 1996
Parviz F.
02/25/14