Hanna M. answered 02/03/17
Tutor
5.0
(795)
Experienced SAT, GRE, Algebra and Math Tutor
Let's say number of minutes used in a month = m
Based on this,
plan A will cost 25 cents(m) = $0.25(m) = 0.25m
plan B will cost $49.95 + 11 cents(m) = $49.95 + $0.11m
In order for plan B to be cheaper than plan A, the following inequality must hold true.
cost of plan A > cost of plan B
0.25m > 49.95 + 0.11m
Subtract 0.11m from both sides to get
0.14m > 49.95
Now, divide both sides by 0.14 to get
m > 356.79
Thus, the smallest possible integer value of m for which plan B is cheaper than plan A is 357 i.e. 357 minutes.
m > 356.79
Thus, the smallest possible integer value of m for which plan B is cheaper than plan A is 357 i.e. 357 minutes.