Solve the solution.

Question

Solve the solution.

 

                                                                                                                         -0.00012t

the amount of carbon-14 present in animal bones after t years is given by y= y of e               . A bone contains 18% of its carbon-14. how old is the bone?

 

the age of the bone is ? years

 

(round to the nearest year)

Answer 1

0.18 = e^(-0.00012t)

 

ln(0.18) = -0.00012t

 

t = - ln(0.18) / 0.00012 ≈ 14289.98690076605833 ≈ 14,290.0 years old