
Steve S. answered 02/20/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
2(1.035)^(x-2006) = 15
log( 2(1.035)^(x-2006) ) = log(15)
log(2) + (x-2006) log(1.035) = log(15)
(x-2006) log(1.035) = log(15) - log(2)
x - 2006 = ( log(15) - log(2) ) / ( log(1.035) )
x = 2006 + ( log(15) - log(2) ) / ( log(1.035) )
x ≈ 2064.57033305908317 ≈ 2064.5703