Search
Ask a question
0

Cell Respiration doubt

Complete oxidation of one molar concentration of glucose (180 g) by aerobic respiration consumes 192 g of oxygen as it produces 264 g of CO2 , 108 g of water and releases 686000 calories.how these values come

1 Answer by Expert Tutors

Tutors, sign in to answer this question.
MARIA M. | Biology and Chemistry TutorBiology and Chemistry Tutor
4.0 4.0 (1 lesson ratings) (1)
0
 
To evaluate these values we need to analyze and balance the chemical reaction first.
 
The typical reaction of the aerobic respiration, or oxidation of glucose in CO2 and H2O is:
 
C6H12O6 + O2 = CO2 +H2O
 
Balanced will be:
 
C6H12O6 + 6O2 =6CO2 +6H2O
 
These amounts are express in mass=g
 
From Stoichiometry the mass  is equal to the Molecular weight, M for the number of moles, n.
 
m= Mn
 
Let's verify these numbers for the mass applying this formula for the Glucose, C6H12O6
 
MC= ~12.01
MH=  ~1.008
MO= ~16.0
 
Where M is for Molecular Weight
 
Is the mass of glucose equal to 180g?
 
C6= 12*6= 72               (M=12, n=6, and so on)
H12= 1*12= 12
O6= 16*6= 96
 
72+12+96=180
 
Yes, they are.
 
Do yourself the rest of calculations to verify the whole process and rest of amounts.