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# Cell Respiration doubt

Complete oxidation of one molar concentration of glucose (180 g) by aerobic respiration consumes 192 g of oxygen as it produces 264 g of CO2 , 108 g of water and releases 686000 calories.how these values come

### 1 Answer by Expert Tutors

MARIA M. | Biology and Chemistry TutorBiology and Chemistry Tutor
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To evaluate these values we need to analyze and balance the chemical reaction first.

The typical reaction of the aerobic respiration, or oxidation of glucose in CO2 and H2O is:

C6H12O6 + O2 = CO2 +H2O

Balanced will be:

C6H12O6 + 6O2 =6CO2 +6H2O

These amounts are express in mass=g

From Stoichiometry the mass  is equal to the Molecular weight, M for the number of moles, n.

m= Mn

Let's verify these numbers for the mass applying this formula for the Glucose, C6H12O6

MC= ~12.01
MH=  ~1.008
MO= ~16.0

Where M is for Molecular Weight

Is the mass of glucose equal to 180g?

C6= 12*6= 72               (M=12, n=6, and so on)
H12= 1*12= 12
O6= 16*6= 96

72+12+96=180

Yes, they are.

Do yourself the rest of calculations to verify the whole process and rest of amounts.