Cell Respiration doubt

Question

Complete oxidation of one molar concentration of glucose (180 g) by aerobic respiration consumes 192 g of oxygen as it produces 264 g of CO2 , 108 g of water and releases 686000 calories.how these values come

Answer 1

 

To evaluate these values we need to analyze and balance the chemical reaction first.

 

The typical reaction of the aerobic respiration, or oxidation of glucose in CO2 and H2O is:

 

C6H12O6 + O2 = CO2 +H2O

 

Balanced will be:

 

C6H12O6 + 6O2 =6CO2 +6H2O

 

These amounts are express in mass=g

 

From Stoichiometry the mass  is equal to the Molecular weight, M for the number of moles, n.

 

m= Mn

 

Let's verify these numbers for the mass applying this formula for the Glucose, C6H12O6

 

MC= ~12.01

MH=  ~1.008

MO= ~16.0

 

Where M is for Molecular Weight

 

Is the mass of glucose equal to 180g?

 

C6= 12*6= 72               (M=12, n=6, and so on)

H12= 1*12= 12

O6= 16*6= 96

 

72+12+96=180

 

Yes, they are.

 

Do yourself the rest of calculations to verify the whole process and rest of amounts.