
Kenneth S. answered 01/07/17
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Two lines containing points numbered A1 A2 A3 A4 A5 A6
and another line containing points numbered B1 B2 B3 B4 B5 B6.
To make a quadrilateral, choose any two "A" points--can be done in 6C2 ways (this is 15 possibilities).
Let's call the segment joining the two points chosen the "top of the quadrilateral."
Now choose any two "B" points--can also be done in 15 ways; from those we draw the segment called "bottom of the quadrilateral."
Example A3 A6
B2 B4.
Just connect the left end point A3 to left endpoint below B2, and similarly connect the two right endpoints. In other words, just finish drawing the quadrilateral.
15 times 15 is 225 possible quadrilaterals.
I leave to you the task of figuring out the answer to the triangles question, #2.


Kenneth S.
Mark, re-read my presented solution again. You will see that the top line segment can be made in 15 distinct ways, there being 6 distinct points--it takes a pair to made one line segment.
Similarly, constructing all possible bottom line segments can be done 15 different ways. Then the rightmost of top & bottom points are connected to make the right side, and the leftmost of chosen bottom vertices are connected to make the left side.
Drawing these sides (the ones not called top & bottom) completes each quadrilateral does not affect the calculation of # of distinct quadrilaterals--it merely completes the diagram for each distinct case. (Forget about diagonals!).
Do you agree that 225 is the correct answer?
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01/07/17
Daniel K.
I cant find the answer for question 2 can u help me?
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01/14/17
Mark M.
01/07/17