Arturo O. answered 01/05/17
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You said for A that the temperature started as "one 20°F". I assume you meant 120°F. Please edit the question. Anyway, here is a solution based on 120°F.
Calorimeter A:
TA(t) = kt + T0
T0 = 120°F
k = rate of temperature change = (100°F - 120ºF) / (10 min) = -2°F/min
Final equation:
TA(t) = -2t + 120, with t in minutes, TA in °F.
Calorimeter B:
Solve in a similar way. You are given kB = 3°F/min
T0B = 20°F
TB(t) = 3t + 20, with t in minutes and TB in °F