Ram K. answered 01/05/17
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KCl + AgNO3 --> KNO3 + AgCl
concentration of AgNO3 = 34g/(108+15+48 = 171g = molar mass of AgNO3)/0.1 litres = 340/171 M = 1.99 M
22.5 cm3 of AgNO3 solution will contain 340/171 *22.5/1000 moles = 0.045 moles. This will react will 0.045 moles of KCl according to the reaction sequence shown above. Since 0.045 moles were contained in 30 cm^3 solution, concentration in moles/liter or moles/dm^3 is 0.045/(30*0.001) = 1.5M or 1.5 moles/dm^3
To get concentration in g/dm^3, multiply this result by the molar mass of KCl, i.e. 1.5M*74g/mol = 111g/dm^3