LAILA H. answered 01/05/17
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cylinder surface area= 2 πrh+2πr2
area of the dipped part=(2 πrh/3)+πr2=2 π*(4)*(7/3)+π(4)2
=108.8 cm2
MD MERAZ A.
asked 01/05/17LAILA H. answered 01/05/17
Tutor for math and physics
Kendra F. answered 01/05/17
Patient & Knowledgeable Math & Science Tutor
= (4cm)2π
= (16cm2)π
= (1/3)(7cm)(8cm)π
= (18.67cm2)π
SA = (16cm2)π + (18.67cm2)π
SA = (34.67cm2)π
SA = 108.91cm2
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