
Al P. answered 12/20/16
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Point slope form of a line has the form y-yo = m(x - xo)
Where m = slope
(xo, yo) = one of the two points
Let's assign (xo, yo) = (0,-3) (it doesn't matter which you choose)
Now calculate m by m = (y1 - yo) / (x1-xo)
m = (3 - (-3)) / (3 - 0) = 6/3 = 2
So the equation for the line, in point-slope form is: y - (-3) = 2(x - 0)
Which may be cleaned up to:
y + 3 = 2x
Check:
3 + 3 = 2(3)
6 = 6 (ok) So the equation agrees (3,3) is on the line
-3 + 3 = 2(0)
0 = 0 (ok) So the equation agrees (0,-3) is also on the line


Al P.
I feel compelled to point out that the two equations are the same (technically, they are "linearly dependent"):
y - 3 = 2(x-3) (the "2nd" equation we found)
y - 3 = 2x - 6
y + 3 = 2x (matches the "1st" equation we found)
This makes sense, as there is only one line, so the two equations need to represent the same thing.
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12/20/16
Al P.
12/20/16