Arturo O. answered 12/01/16
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By Gauss' law,
ΦE = qT/ε0
where qT is the total charge enclosed by the surface. Consider a sphere of radius r > a, concentric with the sphere of radius a. The uniform distribution of q over the inner sphere of radius a ensures the electric field is purely radial, with no angular dependence. This lets you use Gauss' law to find the electric filed at a point on the surface of the sphere of radius r > a.
ΦE = ∫∫E·dA = EA = E(r) (4πr2)
ΦE = qT/ε0 = q/ε0
Then
E(r) (4πr2) = q/ε0
E(r) = q / (4πε0r2) for r > a
Mathematically, it is the same as if all the charge was concentrated at the center of the spheres.
Nadeen N.
12/01/16