J.R. S. answered • 11/23/16

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q = mC∆T

m = mass = 25.0 ml + 50.0 ml = 25.0 g + 50.0 g = 75.0 g since the density is 1 g/ml

C = specific heat = 4.18 J/g/deg

∆T = change in temperature = 33.9 degrees C

q = (75 g)(4.18 J/g/deg)(33.9 deg) = 10628 J = 10.6 kJ heat for this reaction.

If you want enthalpy per mole, then you need to divide this by moles NaOH or H2SO4 present (they are the same), and that would be 0.025 L x 1 mol/L x 2 = 0.005 moles or 0.05 L x 1.0 mole/L = 0.005 (x2 for H2SO4 b/c 2 H+ per mol)

J.R. S.

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Correct. I misread it and thought the increase in temp was 33.9 degrees. My bad.
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06/25/19

Faida B.

why ∆T is not 33.9 -25 ?06/25/19