Steve C. answered 11/21/16
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For this reaction, the mole ratio of SO2 to O2 is 2 to 1. Since there is a direct relationship between moles and liters for gases, the volume ratio is also 2 to 1. The actual volume ratio is 4 to 3. Therefore the oxygen is present in excess. To calculate the mass of SO3, note that 4 L of SO2 will produce 4 L of SO3.
g SO3 = 4 L SO3 (1 mol / 22.4 L)(80.0632 g/ mol) = 14.3 g