Roger N. answered 11/15/16
Tutor
4.9
(290)
. BE in Civil Engineering . Senior Structural/Civil Engineer
let x = side of lawn area
Since the lawn area is a square, then the area of the lawn is = x.x = x2
The side of the lawn and walkway = x + 2m+2m = x+4
The area of the lawn and walkway = (x+4).(x+4) = ( x+4)2
The area of the walkway is then = Area of lawn and walkway - Area of the lawn
That is Area of walkway = (x+4)2 - x2
since the area of the lawn is = to the area of the walkway
x2=(x +4)2-x2 , Rearranging x2+x2=(x+4)2
2x2=x2+8x+16, Rearranging, x2-8x-16=0
solving quadratic equation , a=1, b=-8, c=-16
find Δ = b2 - 4ac = (-8)2 -4(1)(-16) = 64 + 64 = 128
x=-b±√Δ/2a = (8 ± √128)/2 = (8 ± 11.3) /2 = 9.65 m
where x is the length of the side of the lawn
The length of the sidewalk is thus x+2m+2m =
9.65m+2m+2m= 13.65m
Spooj M.
11/15/16