63t2 - 38t - 5 = 0 | Wyzant Ask An Expert

Inactive Tutor answered • 12/07/12

Tutor

New to Wyzant

Robert showed in the other question that you can factorize it. Quadratic formula is shown here: http://www.purplemath.com/modules/quadform.htm

To use the quadratic formula, since it's in the form at² + bt + c = 0, you'll use:

t = [-b ± √(b² - 4ac)]/2a

t = [-(-38) ± √((-38)² - 4(63)(-5))]/(2*63)

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63t2 - 38t - 5 = 0