Parviz F. answered 02/03/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
√(X +4) + 3 = √(3X +1)
[√( X +4) + 3 ] ^2 = (√3X +1 )^2
X+4 + 9 + 6 √( X +4) = 3X +1
X + 13 + 6 √( X + 4) = 3X +1
2X - 12 = 6 √(X +4 )
X - 6 = 3 √( X +4)
X^2 - 12X + 36 = 9 ( X +4)
X^2 -21X =0
X ( X -21 ) =0
X = 0 X =21
Test:
√(21 +4) + 3 √(3 . 21 +1)
(√25+ 3=8 ) = (√64 =8)
X =0
√( 0 +4) +3 √3(0) +1
5 ≠ 1 / Not acceptable