How many grams of HI can be made from 6 grams of H2 and 800 grams of I2 in the following reaction H2 +I2= 2HI

Question

the answer is 768 grams of HI and 38 grams of Iodine in excess. But I don't know how they arrived at this answer

Answer 1

6g H₂ x 1 mol H₂/2.016g H₂ = 3 mol

800g I₂ x 1 mol I₂/253.8g I₂ = 3.15 mol

 

3 mol x (2 mol HI/1 mol H2) x (128g HI/ 1 mol HI) = 768g HI

.15 mol I₂ (253.8g I₂ / 1 mol I₂) = 38g I2