
Victoria V. answered 10/27/16
Tutor
5.0
(402)
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
Hi Ivy.
The key here is knowing that when a plane flies "with the wind", the wind is at is tail, PUSHING it so that it goes its own speed plus the speed of the wind.
Likewise, when a plane flies "into the wind", the wind is pushing the plane back, instead of helping it forward like above. So when the plane flies INTO the wind, the plane's ground speed is not its actual speed, but the speed it would be flying minus the speed at which the wind pushed is back.
So if we let
S= plane's speed in still air
and
W = the speed of the wind
we get two equations:
S + W = 183
(wind pushing on the tail, making the plane travel faster)
and
S - W = 141
(wind pushing on the nose of the plane, slowing it down)
Solve this system of equations and you will have your answer.
Using elimination, add vertically and the "W"s go away, leaving
2S =324
Divide both sides by 2 and get
S = 162 So the plane's speed in still air is 162 km/hr
Substitute this back into either equation and get
S+W=183
162 + W = 183
Subtract 162 from both sides
W = 21 So the wind speed is 21 km/hr.