twice the smallest of three consecutive integers is twelve more than the largest

Question

there seats at a front row play who's numbers were consecutive integers such that twice the smallest was twelve more than the largest 

Answer 1

smallest = x

middle = x + 1

largest = x + 2

 

twice the smallest is twelve more than the largest

 

2x = (x + 2) + 12

2x = x + 14

-x    -x

x = 14

 

the three consecutive integers are 14, 15, 16

 

check:

2(14) = 16 + 12

28 = 28 ♥♥♥

 

 

 

Have a good evening!

Colossians 3:23