Inactive Tutor answered 10/11/16
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asked 10/11/16slope
A line that includes the points (-1,s) and (3,10) has a slope of 5. What is the value of s?
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3 Answers By Expert Tutors
Tutor
New to Wyzant
To find s you need to know the slope-intercept form of a line. That looks like y=mx+b where m is the slope and b is the y-intercept. Now that you know that you can plug in the information you have for the first step.
You have x and y of one of your points and you have the slope so plugging those in looks like:
10=5(3)+b
10=15+b
-5=b
Now that you've solved for b you know the y-intercept for your line. Using that information and the other partial point you've been given you can plug in and find s. It looks like this:
s=5(-1)+ -5
Solve and you find s
s=-5 + -5
s= -10
Inactive Tutor answered 10/11/16
Tutor
New to Wyzant
5=m=(y2-y1)/(x2-x1)=(10-s)/(3+1)
5*4=10-s
20-10=-s
10=-s
s=-10
Inactive Tutor
My answer was already corrected before your comment lol. Yes you are right though s=-10 (:
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10/11/16
Michael A. answered 10/11/16
Tutor
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(2,875)
College Algebra Instructor with 10+ Years' Experience
Given two points on a line, we can determine the slope by finding the difference of the y-coordinates divided by the difference of the x-coordinates. Using that, we can set up the following equation:
(10 - s)/(3 - (-1)) = 5
(10 - s)/4 = 5
10 - s = 20
-s = 10
s = -10
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Michael A.
10/11/16