which point lies on 2x-y+1=0?

Question

I am ayesha and i am 13year old i am weak in maths kindly help me

 

Answer 1

This is an equation of a straight line. It can be rearranged to: y = 2x + 1, which is in the common form of equation

y = mx + b, where m is equal to the slope of the graph, and b is equal to the y-intercept (which means the graph crosses the y-axis at the point (0,1)). There are infinite other points which lie on this line, which you can calculate using various values of x and calculate y from the equation. I hope this is sufficient to answer your question.

Answer 2

To add to Michael's answer, remember that the slope, m, is the same as rise/run or Δy/Δx, where Δy is (y2-y1) and Δx is (x2-x1) for two different points (x1,y1) and (x2,y2). Since you know the point (0,1) is on the line, you want to find the point, (x,y) on your list of options such that the ratio, (y-1)/(x-0), matches the value of m from the equation of the line.