
Kenneth S. answered 09/18/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
For a pair of fair dice, the totals occurring and their # of ways of being achieved, out of a total of 36 possible outcomes, is
Sum Freq
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
P(sum > 8) = (4+3+2+1)/36 = 10/36 = 5/18.
P(even total) = (1+3+5+5+3+1) = 18/36 = 1/2.