Solve the following. Don't forget to cancel out your units.

Question

a. (14.2 g/1) (1 ml/.034 g) = 

 

b. (932.1 L/1) (1000 ml/1L) (4.54 g/mL) = 

 

e. 42.5 g/45.22 cm3 = 

 

 

Thank you!

Answer 1

I'll venture that these are straight-forward conversions shown in factor-label form for a Chemistry class (rather than a math class) to practice making easy cancellations.  Since its only been the first few weeks of the school year, this sort of worksheet needs the teacher to show many examples of what is expected so that you'd be "ready to go"  with the basics, rather than coming in cold and struggling without any context. Anyways, I think the final values you're shooting for are shown below.  You'll have to show how units in the numerator cancel the same units in the denominator.

 

a) 418 ml (given rounding rules for the significant figures)

b) 4,230 kg (tough one to say what would be acceptable since I'm not sure what rounding and significant figure rules you've been given; calculator answer would be 4,231,734 g or 4.23 x 10⁶ g in scientific notation which is a very unusual way to express a large mass in my opinion)

c) 0.940 g/cm³ (again same comments as above with regard to the significant figures).

 

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