If 4g of oxygen diffuse through a very narrow hole how much hydrogen would have diffused under identical conditions

Question

Your options are

• 2g
• 1g
• 4g
• 3g

Answer 1

According to Graham's law, “At constant pressure and temperature, the rate of diffusion or effusion of a gas is inversely proportional to the square root of its vapour density.”
So the rate of diffusion (r) ∝ 1/√d (T and P constant)
For two or more gases at constant pressure and temperature,
r1/r2 = √d2/d1

 

Choice (B) 1g of hydrogen would have been diffused under the identical conditions.

 

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