Raymond B. answered 07/12/25
Math, microeconomics or criminal justice
y= x - (x^3)/6 + (x^5)/120
y = x^2
intersection points are when
(x^5)/120 - (x^3)/6 - x^2 +x = 0
one such a point is (0,0) by inspection, then
x^4)/120 - (x^2)/6 -x +1 = 0
x^4 - 20x^2 -120x +120 = 0
by Descartes sign rule there's 0 or 2 + real solutions= 0 or 2 Positive x intersection points
and 0 or 2 - real solutions = 0 or 2 negative x intersection points, and 0,2 or 4 imaginary solutions
solve by graphing the 4 degree equation in x
2 + x solutions, 0 - x solutions, 2 imaginary solutions
x= about .88 and 6.05, y = .77, 36.60
the 3 intersection points are
(0,0), about (.88, .77) and (6.05, 36.60)