Raymond B. answered 02/14/22
Math, microeconomics or criminal justice
x - x^3/6 +x^5/120 = x^2
x^5/120 -x^3/6 -x^2 + x = 0
x/120[x^4 -20x^2 -120x + 120] = 0
set the factors = 0, solve for x
one point of intersection is the origin (0,0)
there are potentially 4 more. but 2 are imaginary.
the other two x intersections are about (1,0) and (6,0)
but closer to (.8, 0) and (6.05, 0)