Really need help for this question! (URGENT)

Question

The height, y metres, of an object projected directly
upwards from the grouncl can be modelled by
y = 17t-5t^2, where t is the time in seconds after it
leaves the ground.

(iii) 1. 5 seconds after the object has been projected,
a second object is also projected directly
upwards from the ground. Given that the
equations of motion of the two objects are
the same, what is the distance between the
two objects one second after the second
object has been projected?

Answer 1

The key here is figuring out the times.

 

the first object will always be 1.5 seconds more than the second object.

 

so one second after the the second object the times will be this:

 

t for 2nd object will be 1 and t for 1st object will be 2.5

 

then find the heights for both objects

 

and find the difference between the 2

 

Let me know if you need further help on this one

 

Kathy