Norbert W. answered 07/26/16
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The function tanθ) has asymptotes for values (2m + 1)(π/2), for any integer m
For y = -3tan(π/4 * t)
The asymptotes accord for π/4 * t = (2m + 1)(π/2)
t = 4m + 2
Also, since 0 < t < 4
0 < 4m + 2 < 4
-2 < 4m < 2
-1/2 < m < 1/2
The only integer value for m in this range is m = 0
There is one asymptote when t = 2.