
Kenneth S. answered 06/16/16
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I believe that in this problem the ice 'cubes' are not cubes, but spheres, SINCE THEY HAVE A DIAMETER OF 2".
Therefore the volume of the cylindrical glass, (27/2)(pi), is reduced by (4/3)(pi)(13) for each spherical piece of ice;
three such pieces of ice would account for 4pi cu in to be subtracted from the cylindrical volume.
Thus, the volume of water will be 13.5 pi - 4 pi = 9.5 pi.
For this volume of water to be put into the cylinder first, we calculate the height as
V = 9.5 pi = pi (3/2)2h; h = 9.5/(1.52) = 4.2222... inches.

Kenneth S.
06/16/16