Don L. answered 06/06/16
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Jessica, let A represent the adults and let C represent the children. Then we can create two equations to solve.
Equation 1, number of adults and number of children:
A + C = 222
Equation 2, cost for adults and children:
9A + 7C = 1616
Solve the two equations:
A + C = 222
9A + 7C = 1616
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Multiply the first equation by -9 and add:
-9A - 9C = -1998
9A + 7C = 1616
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-2C = -382
Divide both sides by -2:
C = 191, or there were 191 children on the trip.
Substitute for C in the first equation:
A + 191 = 222
Subtract 191 from both sides:
A = 31, or there were 31 adults on the trip.
Solution:
191 child tickets.
31 adult tickets.
Questions?