
Arturo O. answered 06/05/16
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Use speed*time = distance
v = airplane speed in still air
w = wind speed
Against the wind:
(v-w)(3 hrs) = 2190 km ⇒ v-w = 2190/3 = 730
With the wind:
(v+w)(7 hrs) = 8330 km ⇒ v+w = 8330/7 = 1190
Solve a system of two equations in two unknowns:
v - w = 730
v + w = 1190
Add the two equations to get v:
2v = 1190 + 730 = 1920 ⇒ v = 1920/2 = 960 km/hour
Substitute this value of v into either equation, e.g. the top equation:
v - w = 960 - w = 730 ⇒ w = 960 - 730 = 230
Test the answers:
(v-w)(3 hours) = (960 - 230) km/hour * (3 hours) = 2190 km (good)
(v+w)(7 hours) =(960+230) km/hour * (7 hours) = 8330 km (good)
Final answer:
v = 960 km/hour
w = 230 km/hour (This is an exceptionally high wind speed, but it is consistent with the given information.)