Lorena C.
asked • 05/25/16A lamp is labeled 6.0V and 12W.
A.What current flows through the lamp when it is operating?
B. How much energy is supplied to the lamp in 1000 seconds?
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2 Answers By Expert Tutors
Part (A)
Use the equation P = IV where V is the voltage in Volts(V) , I is the current in amperes(A), and P is the power in Watts(W)
Part (B)
Watts are the measured Joules/seconds or J/s
Joules measure energy, so P = E/t, so to find the Energy just do E = P×t
Mark O. answered • 05/25/16
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Hi Lorena,
A. The operating power of a lamp is given by
P = VI
So, solve for I: I = P/V = 12 W / 6.0V = 2A
B. Power is energy / time, or P = W/t where W is the energy. W is referred to as the work. Solve for the work:
W = Pt = (12 W)(1000 s) = 12,000 J
Lorena C.
- What the power supplied to a lamp that is operated by a battery having a 12V potential difference (aka.voltage) across it's terminals when the resistance the lamp is 6.0Ω?
Report
05/25/16
Mark O.
Hi Lorena,
Here you know that in a resistive circuit where the battery has a voltage of 12 V and the resistance of the resistor is 6.0 Ω, you can use Ohm's law to find the current flowing in the circuit: V = IR. Solve for I = V/R = 12 V/ 6.0 Ω = 2 A.
Now that we know the current going through the lamp, we can use the formula for the power delivered by the lamp: P = VI = (12 V) (2 A) = 24 W
Report
05/26/16
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Mark O.
05/25/16