The QUESTION IS IN THE DESCRIPTION BOX AS IT DOESNT FIX IN THE QUESTION BOX.

Question

Jenny, Katie and Lelei each had some sweets. Katie had 8 and Lelei had 14. Jenny gave one-half of her sweets to Katie. Then Katie gave one-half of her total number of sweets to Lelei. Then Lelei gave one-half of her total number of sweets to Jenny. If Jenny ended up with the same number of sweets as she had at the start, how many was that?

Answer 1

Hi Maria

 

Jenny's total at start is X, and we must return back to X at the end.

 

Since Jenny gives half to Katie, that means that Katie will have X/2 + 8.

 

Katie then gives half to Lelei, which means Lelei will have (X/2 + 8)/2 + 14.

 

Now Lelei gives half back to Jenny.

 

this means that ((X/2 + 8)/2 + 14)/2

 

Since we are told that Jenny returns to the original amount, X

 

X/2 = ((X/2 + 8)/2 + 14)/2

 

and you can solve for X

Answer 2

disregard... I reviewed other answers and found my error.

Have a great one.

Answer 3

No. of sweets Jenny has =x

No. of sweets Katie has =8

No. of sweets Lelei has =14

Jenny gave one-half of her sweets to Katie.

So now Jenny has= x/2

Katie has=8 +x/2=(16+x)/2

 

Then Katie gave one-half of her total number of sweets to Lelei

So Lelei has =14 +(16+x)/4=(56+16+x)/4=(72+x)/4

 

Then Lelei gave one-half of her total number of sweets to Jenny

So now Jenny has=x/2 +(72+x)/8=(4x+72+x)/8=(5x+72)/8

 

Jenny ended up with the same number of sweets as she had at the start

 

(5x+72)/8=x

 

5x+72=8x

3x= 72

x=24

 

So Jenny had=24