Find the equation that includes these points: 4,2 0,12

Question

I need help

Answer 1

(x1, x2) = (4,2)  

(y1, y2) = (0,12)

 

Use the slope fprmula to find the slope of the line.

 

m = (y2 - y1)/(x2 - x1)

 

m = (12 - 2)/(0 - 4) = 10/(-4) = -5/2

 

Then use the slope-intercept form to find the equation of the line.

 

y = mx + b

 

Use one of the above points ... I chose (0,12)

Substitute in x=0, y = 12, m = -5/2

 

12 = (-5/2)(0) + b

12 = 0 + b

12 = b

 

Now that we have "b" ... we substitute m and b into the slope intercept form to find our equation.

 

y = mx + b

 

The equation of the line is

 

y = (-5/2)x + 12

Answer 2

First find the slope:

rise/run = (12- 2)/(0-4) = 10/-4 = -5/2

Then substitute the x,y points and b (slope) to find the y-intercept
I'm going to use the point (0,12)
y = m x + b
12 = (-5/2)(0) + b
12 = 0 + b

12 = b

Now you plug in your slope (m) and y-intercept (b) in the formula:
y = mx + b
y = (-5/2)x + 12 This is your answer