Alan G. answered 05/23/16
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Miquela,
What you need to do is reduce the expression, then multiply the numerator and denominator out.
f(x) = (x+1)(x)(x+3)/[(x+2)(x)(x)(x)]
Notice that there is a FACTOR of x in front and after the /. That means you can cancel both off. This leaves:
f(x) = (x+1)(x+3)/[(x+2)x2]
(Note that I wrote (x)(x) as x2, since that is what x2 means.
Now, you can just multiply the numerator and denominator out:
(x+1)(x+3) = x2 + 4x + 3
and
(x+2)x2 = x3 + 2x2.
Putting this together,
f(x) = (x2 + 4x + 3)(x3 + 2x2).
Since you already crossed off all of the common factors, this should be the final, simplified answer.
Let me know if this works out for you.